Weight Calculator - Calculate Weight of a Rod
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1. What is the Weight Calculator?
Definition: The Weight Calculator determines the weight (\(W\)) of a solid rod using the formula \(W = \gamma \cdot A \cdot L\), converting the result to pounds (lb) and kilograms (kg).
Purpose: Assists engineers in calculating the weight of rods, pipes, or bars based on material properties.
Reference:Applied Strength of Materials for Engineering Technology
http://www.etcs.pfw.edu/~dupenb/ET_200/Applied%20Str%20of%20Mat%20for%20ET%20v14%20July%202018.pdf
2. How Does the Calculator Work?
Formula:
\(W = \gamma \cdot A \cdot L\)
Where:
- \(W\): Weight (lb, kg)
- \(\gamma\): Specific weight of the material (lb/in³)
- \(A\): Cross-sectional area (in², calculated as \(\frac{\pi d^2}{4}\))
- \(L\): Length (in)
Steps:
- Step 1: Input Specific Weight. Enter the specific weight (e.g., 0.284 lb/in³).
- Step 2: Input Diameter. Enter the diameter (e.g., 2 in).
- Step 3: Input Length. Enter the length (e.g., 3 ft).
- Step 4: Calculate. The calculator converts units and computes weight in lb and kg.
3. Importance of Weight Calculation
Calculating weight is crucial for:
- Material Selection: Ensures structural components meet weight requirements.
- Design Safety: Prevents overloading due to excessive weight.
- Unit Consistency: Supports conversions from lb/in³ to N/m³ and various length units.
4. Using the Calculator
Example:
Specific Weight = 0.284 lb/in³, Diameter = 2 in, Length = 3 ft:
- Step 1: \(\gamma = 0.284 \, \text{lb/in}^3\).
- Step 2: \(d = 2 \, \text{in}, A = \frac{\pi (2)^2}{4} \approx 3.14 \, \text{in}^2\).
- Step 3: \(L = 3 \, \text{ft} = 36 \, \text{in}\).
- Step 4: \(W = 0.284 \cdot 3.14 \cdot 36 \approx 32.1 \, \text{lb}, 14.56 \, \text{kg}\).
5. Frequently Asked Questions (FAQ)
Q: What is weight?
A: Weight is the force exerted by a material due to gravity, calculated from its volume and specific weight.
Q: Why convert units?
A: The calculator ensures consistent units (lb/in³ and inches) for accurate results and provides output in kg.
Q: Is this accurate for all rods?
A: Yes, if the specific weight, diameter, and length are correctly measured.