Definition: This calculator computes the result of raising the imaginary unit \( i \) (where \( i = \sqrt{-1} \)) to any integer power \( n \), i.e., \( i^n \). The powers of \( i \) follow a repeating cycle of length 4: \( i^0 = 1 \), \( i^1 = i \), \( i^2 = -1 \), \( i^3 = -i \).
Purpose: It helps users quickly determine the value of \( i^n \) for any integer \( n \), which is useful in complex number arithmetic, algebra, and related fields like physics and engineering.
The calculator uses the cyclic property of the powers of \( i \), which repeat every four exponents:
To compute \( i^n \), the calculator:
Steps:
The powers of \( i \) are important for:
Example 1 (Positive Exponent): Calculate \( i^{123} \):
Example 2 (Negative Exponent): Calculate \( i^{-5} \):
Q: What is the imaginary unit \( i \)?
A: The imaginary unit \( i \) is defined as \( i = \sqrt{-1} \), so \( i^2 = -1 \). It is a fundamental concept in complex numbers.
Q: Why do the powers of \( i \) repeat every four exponents?
A: The powers of \( i \) form a cycle because \( i^4 = (i^2)^2 = (-1)^2 = 1 \), and then the pattern repeats: \( i^4 = 1 \), \( i^5 = i \), and so on.
Q: Can this calculator handle negative exponents?
A: Yes, the calculator computes \( i^n \) for any integer \( n \), including negative exponents, by using the cyclic property of \( i \).